2x^3y^2-3x^4y^5=

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Solution for 2x^3y^2-3x^4y^5= equation:


Simplifying
2x3y2 + -3x4y5 = 0

Solving
2x3y2 + -3x4y5 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), 'x3y2'.
x3y2(2 + -3xy3) = 0

Subproblem 1

Set the factor 'x3y2' equal to zero and attempt to solve: Simplifying x3y2 = 0 Solving x3y2 = 0 Move all terms containing x to the left, all other terms to the right. Simplifying x3y2 = 0 The solution to this equation could not be determined. This subproblem is being ignored because a solution could not be determined.

Subproblem 2

Set the factor '(2 + -3xy3)' equal to zero and attempt to solve: Simplifying 2 + -3xy3 = 0 Solving 2 + -3xy3 = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3xy3 = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -3xy3 = 0 + -2 -3xy3 = 0 + -2 Combine like terms: 0 + -2 = -2 -3xy3 = -2 Divide each side by '-3y3'. x = 0.6666666667y-3 Simplifying x = 0.6666666667y-3

Solution

x = {0.6666666667y-3}

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